What are the solutions to the equation 2x^2+5x-3=x^2-x+13 ?

The solutions to the equation 2x^2+5x-3=x^2-x+13 are x=2,x=-8

Find the zeros of 2x^2+5x-3=x^2-x+13

The zeros of 2x^2+5x-3=x^2-x+13 are x=2,x=-8

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2 x^{2} + 5 x - 3 = x^{2} - x + 13

x = 2, x = - 8

Solution steps

2 x^{2} + 5 x - 3 = x^{2} - x + 13

Move

13

to the left side

2 x^{2} + 5 x - 16 = x^{2} - x

Move

x

to the left side

2 x^{2} + 6 x - 16 = x^{2}

Move

x^{2}

to the left side

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

7 m^{2} - 27 m + 18 = 0

4 x \cdot 3 x = 3072

4 x (3 + 5 x) = 0

y^{2} + y = 3

x^{2} + x - 7 - 5 = 0

What are the solutions to the equation 2x^2+5x-3=x^2-x+13 ?
The solutions to the equation 2x^2+5x-3=x^2-x+13 are x=2,x=-8
Find the zeros of 2x^2+5x-3=x^2-x+13
The zeros of 2x^2+5x-3=x^2-x+13 are x=2,x=-8