What are the solutions to the equation (0-2)^2-(y-1)^2=9 ?

The solutions to the equation (0-2)^2-(y-1)^2=9 are y=sqrt(5)i+1,y=-sqrt(5)i+1

Find the zeros of (0-2)^2-(y-1)^2=9

The zeros of (0-2)^2-(y-1)^2=9 are y=sqrt(5)i+1,y=-sqrt(5)i+1

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(0 - 2)^{2} - (y - 1)^{2} = 9

y = 5 i + 1, y = - 5 i + 1

Solution steps

(0 - 2)^{2} - (y - 1)^{2} = 9

Move

(0 - 2)^{2}

to the right side

- (y - 1)^{2} = 5

Divide both sides by

- 1

(y - 1)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 1 = - 5 : y = 5 i + 1

Solve

y - 1 = - - 5 : y = - 5 i + 1

The solutions to the quadratic equation are:

y = 5 i + 1, y = - 5 i + 1

0.25 x^{2} - 350 x - 100000 = 0

1 - 3 x - 2 x^{2} = 0

8^{2} + 6^{2} = X^{2}

3 y^{2} - 2 y - 4 = 0

v^{2} - 2 v - 35 = 0

What are the solutions to the equation (0-2)^2-(y-1)^2=9 ?
The solutions to the equation (0-2)^2-(y-1)^2=9 are y=sqrt(5)i+1,y=-sqrt(5)i+1
Find the zeros of (0-2)^2-(y-1)^2=9
The zeros of (0-2)^2-(y-1)^2=9 are y=sqrt(5)i+1,y=-sqrt(5)i+1