What are the solutions to the equation 6x^2-7x+6=0 ?

The solutions to the equation 6x^2-7x+6=0 are x= 7/12+i(sqrt(95))/(12),x= 7/12-i(sqrt(95))/(12)

Find the zeros of 6x^2-7x+6=0

The zeros of 6x^2-7x+6=0 are x= 7/12+i(sqrt(95))/(12),x= 7/12-i(sqrt(95))/(12)

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6 x^{2} - 7 x + 6 = 0

x = \frac{7}{12} + i \frac{95}{12}, x = \frac{7}{12} - i \frac{95}{12}

Solution steps

6 x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

(- 7)^{2} - 4 \cdot 6 \cdot 6 : 95 i

x_{1, 2} = \frac{- ( - 7 ) \pm 95 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 95 i}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 95 i}{2 \cdot 6}

x = \frac{- ( - 7 ) + 95 i}{2 \cdot 6} : \frac{7}{12} + i \frac{95}{12}

x = \frac{- ( - 7 ) - 95 i}{2 \cdot 6} : \frac{7}{12} - i \frac{95}{12}

The solutions to the quadratic equation are:

x = \frac{7}{12} + i \frac{95}{12}, x = \frac{7}{12} - i \frac{95}{12}

- 5 (3 x + 15) (x - 6) = 0

2 x^{2} = 5 x + 63

4 x^{2} + 6 + 4 x = 4 x

(x + 5)^{2} - 36 = 0

4 x^{2} = 8 x - 3

What are the solutions to the equation 6x^2-7x+6=0 ?
The solutions to the equation 6x^2-7x+6=0 are x= 7/12+i(sqrt(95))/(12),x= 7/12-i(sqrt(95))/(12)
Find the zeros of 6x^2-7x+6=0
The zeros of 6x^2-7x+6=0 are x= 7/12+i(sqrt(95))/(12),x= 7/12-i(sqrt(95))/(12)