What is (4-2i)/(4+6i) ?

The solution to (4-2i)/(4+6i) is 1/13-8/13 i

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simplify (4-2i)/(4+6i)

simplify

\frac{4 - 2 i}{4 + 6 i}

\frac{1}{13} - \frac{8}{13} i

Solution steps

\frac{4 - 2 i}{4 + 6 i}

Multiply by the conjugate

\frac{4 - 6 i}{4 - 6 i}

= \frac{( 4 - 2 i ) ( 4 - 6 i )}{( 4 + 6 i ) ( 4 - 6 i )}

Simplify

\frac{( 4 - 2 i ) ( 4 - 6 i )}{( 4 + 6 i ) ( 4 - 6 i )} : \frac{4 - 32 i}{52}

= \frac{4 - 32 i}{52}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{4}{52} + \frac{- 32}{52} i

Simplify

\frac{4}{52} + \frac{- 32}{52} i : \frac{1}{13} - \frac{8}{13} i

= \frac{1}{13} - \frac{8}{13} i

2 x^{2} + x y - 3 y^{2}

- 10 r = - 10

(4 x - 9)^{4} (x - 1)^{3} (x + 1) \leq 0

(\frac{2}{8})^{3}

\frac{1}{3} \cdot \frac{1}{2}