What are the solutions to the equation completesquare 2x^2+x=1 ?

The solutions to the equation completesquare 2x^2+x=1 are x= 1/2 ,x=-1

Find the zeros of completesquare 2x^2+x=1

The zeros of completesquare 2x^2+x=1 are x= 1/2 ,x=-1

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2 x^{2} + x = 1

x = \frac{1}{2}, x = - 1

Decimal Notation

x = 0.5, x = - 1

Solution steps

2 x^{2} + x = 1

Divide both sides by

2

\frac{2 x ^{2} + x}{2} = \frac{1}{2}

x^{2} + \frac{x}{2} = \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{1}{4})^{2} = \frac{9}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{1}{4} = \frac{9}{16} : x = \frac{1}{2}

Solve

x + \frac{1}{4} = - \frac{9}{16} : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 1

2 y^{2} + 2 y - 2 = 0

x = x^{2} + 3 x - 2

x^{2} = 64

x^{2} + \frac{3}{2} x - 7 = 0

2 x (x + 2) + x + 2 = 5

What are the solutions to the equation completesquare 2x^2+x=1 ?
The solutions to the equation completesquare 2x^2+x=1 are x= 1/2 ,x=-1
Find the zeros of completesquare 2x^2+x=1
The zeros of completesquare 2x^2+x=1 are x= 1/2 ,x=-1