What are the solutions to the equation x^2-4x+4=-25 ?

The solutions to the equation x^2-4x+4=-25 are x=2+5i,x=2-5i

Find the zeros of x^2-4x+4=-25

The zeros of x^2-4x+4=-25 are x=2+5i,x=2-5i

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x^{2} - 4 x + 4 = - 25

x = 2 + 5 i, x = 2 - 5 i

Solution steps

x^{2} - 4 x + 4 = - 25

Move

25

to the left side

x^{2} - 4 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 29 : 10 i

x_{1, 2} = \frac{- ( - 4 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10 i}{2 \cdot 1} : 2 + 5 i

x = \frac{- ( - 4 ) - 10 i}{2 \cdot 1} : 2 - 5 i

The solutions to the quadratic equation are:

x = 2 + 5 i, x = 2 - 5 i

x, w = 2 x^{2} + 3

x + 1 = x^{2} - 2 x + 1

(x)^{2} + (- \frac{3}{7})^{2} = 1

4 x^{2} + 4 = 5 x

- 0.0625 x^{2} + 2 x + 50 = 60

What are the solutions to the equation x^2-4x+4=-25 ?
The solutions to the equation x^2-4x+4=-25 are x=2+5i,x=2-5i
Find the zeros of x^2-4x+4=-25
The zeros of x^2-4x+4=-25 are x=2+5i,x=2-5i