What are the solutions to the equation 0=-16t^2+16t+64 ?

The solutions to the equation 0=-16t^2+16t+64 are t=-(-1+sqrt(17))/2 ,t=(1+sqrt(17))/2

Find the zeros of 0=-16t^2+16t+64

The zeros of 0=-16t^2+16t+64 are t=-(-1+sqrt(17))/2 ,t=(1+sqrt(17))/2

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0 = - 16 t^{2} + 16 t + 64

t = - \frac{- 1 + 17}{2}, t = \frac{1 + 17}{2}

Decimal Notation

t = - 1.56155 \dots, t = 2.56155 \dots

Solution steps

0 = - 16 t^{2} + 16 t + 64

Switch sides

- 16 t^{2} + 16 t + 64 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 64}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 64 = 1617

t_{1, 2} = \frac{- 16 \pm 16 17}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 16 17}{2 ( - 16 )}, t_{2} = \frac{- 16 - 16 17}{2 ( - 16 )}

t = \frac{- 16 + 16 17}{2 ( - 16 )} : - \frac{- 1 + 17}{2}

t = \frac{- 16 - 16 17}{2 ( - 16 )} : \frac{1 + 17}{2}

The solutions to the quadratic equation are:

t = - \frac{- 1 + 17}{2}, t = \frac{1 + 17}{2}

(x + 3) (2 x - 4) = 0

(y - 4)^{2} = - 100

4 x^{2} = - 36 x - 87

a, 3 a [7 a^{2} b^{3}] = 12 a^{3} b^{3}

3 a^{2} - 75 = 0

What are the solutions to the equation 0=-16t^2+16t+64 ?
The solutions to the equation 0=-16t^2+16t+64 are t=-(-1+sqrt(17))/2 ,t=(1+sqrt(17))/2
Find the zeros of 0=-16t^2+16t+64
The zeros of 0=-16t^2+16t+64 are t=-(-1+sqrt(17))/2 ,t=(1+sqrt(17))/2