What are the solutions to the equation solvefor c,16c^2-200c+49=0 ?

The solutions to the equation solvefor c,16c^2-200c+49=0 are c= 49/4 ,c= 1/4

Find the zeros of solvefor c,16c^2-200c+49=0

The zeros of solvefor c,16c^2-200c+49=0 are c= 49/4 ,c= 1/4

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c, 16 c^{2} - 200 c + 49 = 0

c = \frac{49}{4}, c = \frac{1}{4}

Decimal Notation

c = 12.25, c = 0.25

Solution steps

16 c^{2} - 200 c + 49 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 16 \cdot 49}{2 \cdot 16}

(- 200)^{2} - 4 \cdot 16 \cdot 49 = 192

c_{1, 2} = \frac{- ( - 200 ) \pm 192}{2 \cdot 16}

Separate the solutions

c_{1} = \frac{- ( - 200 ) + 192}{2 \cdot 16}, c_{2} = \frac{- ( - 200 ) - 192}{2 \cdot 16}

c = \frac{- ( - 200 ) + 192}{2 \cdot 16} : \frac{49}{4}

c = \frac{- ( - 200 ) - 192}{2 \cdot 16} : \frac{1}{4}

The solutions to the quadratic equation are:

c = \frac{49}{4}, c = \frac{1}{4}

3 b^{2} + 1 = - 2 b

x^{2} + 3 x - 68 = 3 x - 43 x - 4

9 w^{2} + 4 = 0

9 x - 4 x^{2} = 7

x^{2} - 18 x + 3 = 0

What are the solutions to the equation solvefor c,16c^2-200c+49=0 ?
The solutions to the equation solvefor c,16c^2-200c+49=0 are c= 49/4 ,c= 1/4
Find the zeros of solvefor c,16c^2-200c+49=0
The zeros of solvefor c,16c^2-200c+49=0 are c= 49/4 ,c= 1/4