What are the solutions to the equation 1-0.4L-0.2L^2=0 ?

The solutions to the equation 1-0.4L-0.2L^2=0 are L=-1-sqrt(6),L=sqrt(6)-1

Find the zeros of 1-0.4L-0.2L^2=0

The zeros of 1-0.4L-0.2L^2=0 are L=-1-sqrt(6),L=sqrt(6)-1

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1 - 0.4 L - 0.2 L^{2} = 0

L = - 1 - 6, L = 6 - 1

Decimal Notation

L = - 3.44948 \dots, L = 1.44948 \dots

Solution steps

1 - 0.4 L - 0.2 L^{2} = 0

Multiply both sides by

10

10 - 4 L - 2 L^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 L^{2} - 4 L + 10 = 0

Solve with the quadratic formula

L_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 10 = 46

L_{1, 2} = \frac{- ( - 4 ) \pm 4 6}{2 ( - 2 )}

Separate the solutions

L_{1} = \frac{- ( - 4 ) + 4 6}{2 ( - 2 )}, L_{2} = \frac{- ( - 4 ) - 4 6}{2 ( - 2 )}

L = \frac{- ( - 4 ) + 4 6}{2 ( - 2 )} : - 1 - 6

L = \frac{- ( - 4 ) - 4 6}{2 ( - 2 )} : 6 - 1

The solutions to the quadratic equation are:

L = - 1 - 6, L = 6 - 1

x^{2} - 13 + 2 x + 49 = 116

x^{2} + 3 x + 2.25 = 0

3 x^{2} - 11 x = - 7 x - 4

10 x^{2} - 19 x - 12 = 0

t^{2} = 3 (t - 1)

What are the solutions to the equation 1-0.4L-0.2L^2=0 ?
The solutions to the equation 1-0.4L-0.2L^2=0 are L=-1-sqrt(6),L=sqrt(6)-1
Find the zeros of 1-0.4L-0.2L^2=0
The zeros of 1-0.4L-0.2L^2=0 are L=-1-sqrt(6),L=sqrt(6)-1