What are the solutions to the equation x(x-4)=4 ?

The solutions to the equation x(x-4)=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

Find the zeros of x(x-4)=4

The zeros of x(x-4)=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

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x (x - 4) = 4

x = 2 (1 + 2), x = 2 (1 - 2)

Decimal Notation

x = 4.82842 \dots, x = - 0.82842 \dots

Solution steps

x (x - 4) = 4

Expand

x (x - 4) : x^{2} - 4 x

x^{2} - 4 x = 4

Move

4

to the left side

x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 2}{2 \cdot 1} : 2 (1 + 2)

x = \frac{- ( - 4 ) - 4 2}{2 \cdot 1} : 2 (1 - 2)

The solutions to the quadratic equation are:

x = 2 (1 + 2), x = 2 (1 - 2)

x^{2} - 8 x = - 5 (\frac{1}{2})

3 x^{2} - 6 x - 2 = 4 + 5 x - 7 x^{2}

2 a^{2} - 5 a - 2 = 0

5 x^{2} - 7 x = 2 x (x - 3)

100 x^{2} - x + 1 = 0

What are the solutions to the equation x(x-4)=4 ?
The solutions to the equation x(x-4)=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))
Find the zeros of x(x-4)=4
The zeros of x(x-4)=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))