What are the solutions to the equation 6b^2-16b-92=-6b ?

The solutions to the equation 6b^2-16b-92=-6b are b=(5+sqrt(577))/6 ,b=(5-sqrt(577))/6

Find the zeros of 6b^2-16b-92=-6b

The zeros of 6b^2-16b-92=-6b are b=(5+sqrt(577))/6 ,b=(5-sqrt(577))/6

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6 b^{2} - 16 b - 92 = - 6 b

b = \frac{5 + 577}{6}, b = \frac{5 - 577}{6}

Decimal Notation

b = 4.83680 \dots, b = - 3.17013 \dots

Solution steps

6 b^{2} - 16 b - 92 = - 6 b

Move

6 b

to the left side

6 b^{2} - 10 b - 92 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 ( - 92 )}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 (- 92) = 2577

b_{1, 2} = \frac{- ( - 10 ) \pm 2 577}{2 \cdot 6}

Separate the solutions

b_{1} = \frac{- ( - 10 ) + 2 577}{2 \cdot 6}, b_{2} = \frac{- ( - 10 ) - 2 577}{2 \cdot 6}

b = \frac{- ( - 10 ) + 2 577}{2 \cdot 6} : \frac{5 + 577}{6}

b = \frac{- ( - 10 ) - 2 577}{2 \cdot 6} : \frac{5 - 577}{6}

The solutions to the quadratic equation are:

b = \frac{5 + 577}{6}, b = \frac{5 - 577}{6}

6 x (x - 1) = 18 - 29 x

x^{2} - 3 x = 4 x - 12

1 2^{2} + b^{2} = (2 b)^{2}

x = \frac{x ^{2}}{9} - \frac{2 x}{3}

(y - 5)^{2} - 11 (y - 5) + 24 = 0

What are the solutions to the equation 6b^2-16b-92=-6b ?
The solutions to the equation 6b^2-16b-92=-6b are b=(5+sqrt(577))/6 ,b=(5-sqrt(577))/6
Find the zeros of 6b^2-16b-92=-6b
The zeros of 6b^2-16b-92=-6b are b=(5+sqrt(577))/6 ,b=(5-sqrt(577))/6