What are the solutions to the equation (9z+5)^2=0 ?

The solutions to the equation (9z+5)^2=0 are z=-5/9

Find the zeros of (9z+5)^2=0

The zeros of (9z+5)^2=0 are z=-5/9

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(9 z + 5)^{2} = 0

z = - \frac{5}{9}

Decimal Notation

z = - 0.55555 \dots

Solution steps

(9 z + 5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

9 z + 5 = 0 : z = - \frac{5}{9}

The solution to the quadratic equation is:

z = - \frac{5}{9}

5 a^{2} - 6 a + 10 = 0

2 x^{2} - 26 x + 72 = 0

x^{2} = 8 (x + 6)

3 x^{2} + 26 x = 14 x + 135

39.2 t - 4.9 t^{2} = 0

What are the solutions to the equation (9z+5)^2=0 ?
The solutions to the equation (9z+5)^2=0 are z=-5/9
Find the zeros of (9z+5)^2=0
The zeros of (9z+5)^2=0 are z=-5/9