What are the solutions to the equation 4p^2-5p-51=0 ?

The solutions to the equation 4p^2-5p-51=0 are p= 17/4 ,p=-3

Find the zeros of 4p^2-5p-51=0

The zeros of 4p^2-5p-51=0 are p= 17/4 ,p=-3

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4 p^{2} - 5 p - 51 = 0

p = \frac{17}{4}, p = - 3

Decimal Notation

p = 4.25, p = - 3

Solution steps

4 p^{2} - 5 p - 51 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 51 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 51) = 29

p_{1, 2} = \frac{- ( - 5 ) \pm 29}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 29}{2 \cdot 4}, p_{2} = \frac{- ( - 5 ) - 29}{2 \cdot 4}

p = \frac{- ( - 5 ) + 29}{2 \cdot 4} : \frac{17}{4}

p = \frac{- ( - 5 ) - 29}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

p = \frac{17}{4}, p = - 3

2 x^{(2)} + 3 = 6 x

x, f = u (x^{2})

- x^{2} - 2 x + 8

x^{2} + 62525 x + 62500000 = 0

108 = - 16 t^{2} - 22 t + 220

What are the solutions to the equation 4p^2-5p-51=0 ?
The solutions to the equation 4p^2-5p-51=0 are p= 17/4 ,p=-3
Find the zeros of 4p^2-5p-51=0
The zeros of 4p^2-5p-51=0 are p= 17/4 ,p=-3