What are the solutions to the equation -2m^2-28m-98=0 ?

The solutions to the equation -2m^2-28m-98=0 are m=-7

Find the zeros of -2m^2-28m-98=0

The zeros of -2m^2-28m-98=0 are m=-7

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- 2 m^{2} - 28 m - 98 = 0

m = - 7

Solution steps

- 2 m^{2} - 28 m - 98 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 2 ) ( - 98 )}{2 ( - 2 )}

(- 28)^{2} - 4 (- 2) (- 98) = 0

m_{1, 2} = \frac{- ( - 28 ) \pm 0}{2 ( - 2 )}

m = \frac{- ( - 28 )}{2 ( - 2 )}

\frac{- ( - 28 )}{2 ( - 2 )} = - 7

m = - 7

The solution to the quadratic equation is:

m = - 7

10 x^{2} + 6 x - 4 = 0

x^{2} + 11 x = - 24

x^{2} - (8 \cdot x) = 9

x^{2} - 16 = 0

\frac{x}{2} = x^{2} - \frac{3}{2}

What are the solutions to the equation -2m^2-28m-98=0 ?
The solutions to the equation -2m^2-28m-98=0 are m=-7
Find the zeros of -2m^2-28m-98=0
The zeros of -2m^2-28m-98=0 are m=-7