What are the solutions to the equation -2y^2-14y+5=0 ?

The solutions to the equation -2y^2-14y+5=0 are y=-(7+sqrt(59))/2 ,y=(sqrt(59)-7)/2

Find the zeros of -2y^2-14y+5=0

The zeros of -2y^2-14y+5=0 are y=-(7+sqrt(59))/2 ,y=(sqrt(59)-7)/2

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- 2 y^{2} - 14 y + 5 = 0

y = - \frac{7 + 59}{2}, y = \frac{59 - 7}{2}

Decimal Notation

y = - 7.34057 \dots, y = 0.34057 \dots

Solution steps

- 2 y^{2} - 14 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 14)^{2} - 4 (- 2) \cdot 5 = 259

y_{1, 2} = \frac{- ( - 14 ) \pm 2 59}{2 ( - 2 )}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 59}{2 ( - 2 )}, y_{2} = \frac{- ( - 14 ) - 2 59}{2 ( - 2 )}

y = \frac{- ( - 14 ) + 2 59}{2 ( - 2 )} : - \frac{7 + 59}{2}

y = \frac{- ( - 14 ) - 2 59}{2 ( - 2 )} : \frac{59 - 7}{2}

The solutions to the quadratic equation are:

y = - \frac{7 + 59}{2}, y = \frac{59 - 7}{2}

2 x^{2} - 21 x + 54 = 0

b^{2} + b = 42

3 y^{2} + 5 y + 4 = 2

4^{2} = 2 x^{2}

v^{2} = - 16 - 10 v

What are the solutions to the equation -2y^2-14y+5=0 ?
The solutions to the equation -2y^2-14y+5=0 are y=-(7+sqrt(59))/2 ,y=(sqrt(59)-7)/2
Find the zeros of -2y^2-14y+5=0
The zeros of -2y^2-14y+5=0 are y=-(7+sqrt(59))/2 ,y=(sqrt(59)-7)/2