What are the solutions to the equation 5x-3=2x^2 ?

The solutions to the equation 5x-3=2x^2 are x= 3/2 ,x=1

Find the zeros of 5x-3=2x^2

The zeros of 5x-3=2x^2 are x= 3/2 ,x=1

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5 x - 3 = 2 x^{2}

x = \frac{3}{2}, x = 1

Decimal Notation

x = 1.5, x = 1

Solution steps

5 x - 3 = 2 x^{2}

Switch sides

2 x^{2} = 5 x - 3

Move

3

to the left side

2 x^{2} + 3 = 5 x

Move

5 x

to the left side

2 x^{2} + 3 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

x = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 1

x^{2} + 12 x = 0

x, - 6 x y - x^{2} + 3 x = 0

- 2 x^{2} + 20 x - 42 = 0

2 x^{2} - 4 x + 27 = 0

5 x^{2} = 47 x + 30

What are the solutions to the equation 5x-3=2x^2 ?
The solutions to the equation 5x-3=2x^2 are x= 3/2 ,x=1
Find the zeros of 5x-3=2x^2
The zeros of 5x-3=2x^2 are x= 3/2 ,x=1