What are the solutions to the equation (8+x)*3x-(8+x)*7=0 ?

The solutions to the equation (8+x)*3x-(8+x)*7=0 are x= 7/3 ,x=-8

Find the zeros of (8+x)*3x-(8+x)*7=0

The zeros of (8+x)*3x-(8+x)*7=0 are x= 7/3 ,x=-8

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(8 + x) \cdot 3 x - (8 + x) \cdot 7 = 0

x = \frac{7}{3}, x = - 8

Decimal Notation

x = 2.33333 \dots, x = - 8

Solution steps

(8 + x) \cdot 3 x - (8 + x) \cdot 7 = 0

Expand

(8 + x) \cdot 3 x - (8 + x) \cdot 7 : 3 x^{2} + 17 x - 56

3 x^{2} + 17 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 ( - 56 )}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 (- 56) = 31

x_{1, 2} = \frac{- 17 \pm 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 31}{2 \cdot 3}, x_{2} = \frac{- 17 - 31}{2 \cdot 3}

x = \frac{- 17 + 31}{2 \cdot 3} : \frac{7}{3}

x = \frac{- 17 - 31}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 8

c^{2} - 32 = 0

3 x^{2} + x - 1 = (2 x + 9) (x - 1)

x, 3 x^{2} - 5 x = 3 x + 5

5 x^{2} = 6

x, x^{2} - 2 x y + y^{2} = 4

What are the solutions to the equation (8+x)*3x-(8+x)*7=0 ?
The solutions to the equation (8+x)*3x-(8+x)*7=0 are x= 7/3 ,x=-8
Find the zeros of (8+x)*3x-(8+x)*7=0
The zeros of (8+x)*3x-(8+x)*7=0 are x= 7/3 ,x=-8