What are the solutions to the equation -3u^2-u+2=0 ?

The solutions to the equation -3u^2-u+2=0 are u=-1,u= 2/3

Find the zeros of -3u^2-u+2=0

The zeros of -3u^2-u+2=0 are u=-1,u= 2/3

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- 3 u^{2} - u + 2 = 0

u = - 1, u = \frac{2}{3}

Decimal Notation

u = - 1, u = 0.66666 \dots

Solution steps

- 3 u^{2} - u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 1)^{2} - 4 (- 3) \cdot 2 = 5

u_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 3 )}

Separate the solutions

u_{1} = \frac{- ( - 1 ) + 5}{2 ( - 3 )}, u_{2} = \frac{- ( - 1 ) - 5}{2 ( - 3 )}

u = \frac{- ( - 1 ) + 5}{2 ( - 3 )} : - 1

u = \frac{- ( - 1 ) - 5}{2 ( - 3 )} : \frac{2}{3}

The solutions to the quadratic equation are:

u = - 1, u = \frac{2}{3}

3 - x^{2} = 2 x^{2} + 1

2 x^{2} = - 3 x - 4

15 x^{2} - 10 x + 1 = 3 x - 1

\frac{1}{8} x^{2} + 16 = 0

4 + 19 x - 5 x^{2} = 0

What are the solutions to the equation -3u^2-u+2=0 ?
The solutions to the equation -3u^2-u+2=0 are u=-1,u= 2/3
Find the zeros of -3u^2-u+2=0
The zeros of -3u^2-u+2=0 are u=-1,u= 2/3