What are the solutions to the equation 16s^2+72s=-81 ?

The solutions to the equation 16s^2+72s=-81 are s=-9/4

Find the zeros of 16s^2+72s=-81

The zeros of 16s^2+72s=-81 are s=-9/4

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16 s^{2} + 72 s = - 81

s = - \frac{9}{4}

Decimal Notation

s = - 2.25

Solution steps

16 s^{2} + 72 s = - 81

Move

81

to the left side

16 s^{2} + 72 s + 81 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 16 \cdot 81}{2 \cdot 16}

7 2^{2} - 4 \cdot 16 \cdot 81 = 0

s_{1, 2} = \frac{- 72 \pm 0}{2 \cdot 16}

s = \frac{- 72}{2 \cdot 16}

\frac{- 72}{2 \cdot 16} = - \frac{9}{4}

s = - \frac{9}{4}

The solution to the quadratic equation is:

s = - \frac{9}{4}

- x^{2} + 9 x = 4 x + 36

3 + x - x^{2}

4 x^{2} - 8 x - 10 = 0

6 x^{2} - 10 x = 4

(3 x + 4)^{2} = 2

What are the solutions to the equation 16s^2+72s=-81 ?
The solutions to the equation 16s^2+72s=-81 are s=-9/4
Find the zeros of 16s^2+72s=-81
The zeros of 16s^2+72s=-81 are s=-9/4