What are the solutions to the equation -2x^2-7x-1=0 ?

The solutions to the equation -2x^2-7x-1=0 are x=-(7+sqrt(41))/4 ,x=-(7-sqrt(41))/4

Find the zeros of -2x^2-7x-1=0

The zeros of -2x^2-7x-1=0 are x=-(7+sqrt(41))/4 ,x=-(7-sqrt(41))/4

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- 2 x^{2} - 7 x - 1 = 0

x = - \frac{7 + 41}{4}, x = - \frac{7 - 41}{4}

Decimal Notation

x = - 3.35078 \dots, x = - 0.14921 \dots

Solution steps

- 2 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

(- 7)^{2} - 4 (- 2) (- 1) = 41

x_{1, 2} = \frac{- ( - 7 ) \pm 41}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 41}{2 ( - 2 )}, x_{2} = \frac{- ( - 7 ) - 41}{2 ( - 2 )}

x = \frac{- ( - 7 ) + 41}{2 ( - 2 )} : - \frac{7 + 41}{4}

x = \frac{- ( - 7 ) - 41}{2 ( - 2 )} : - \frac{7 - 41}{4}

The solutions to the quadratic equation are:

x = - \frac{7 + 41}{4}, x = - \frac{7 - 41}{4}

3 x^{2} + 2 x - 6

s^{2} = 25

(x + 5)^{3} - x^{3} - 1 5^{2} = 50

y^{2} - y - 3 = 0

- 5 k^{2} = - 20

What are the solutions to the equation -2x^2-7x-1=0 ?
The solutions to the equation -2x^2-7x-1=0 are x=-(7+sqrt(41))/4 ,x=-(7-sqrt(41))/4
Find the zeros of -2x^2-7x-1=0
The zeros of -2x^2-7x-1=0 are x=-(7+sqrt(41))/4 ,x=-(7-sqrt(41))/4