What are the solutions to the equation 7b-3b^2=5b^2 ?

The solutions to the equation 7b-3b^2=5b^2 are b=0,b= 7/8

Find the zeros of 7b-3b^2=5b^2

The zeros of 7b-3b^2=5b^2 are b=0,b= 7/8

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7 b - 3 b^{2} = 5 b^{2}

b = 0, b = \frac{7}{8}

Decimal Notation

b = 0, b = 0.875

Solution steps

7 b - 3 b^{2} = 5 b^{2}

Move

5 b^{2}

to the left side

7 b - 8 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 b^{2} + 7 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

7^{2} - 4 (- 8) \cdot 0 = 7

b_{1, 2} = \frac{- 7 \pm 7}{2 ( - 8 )}

Separate the solutions

b_{1} = \frac{- 7 + 7}{2 ( - 8 )}, b_{2} = \frac{- 7 - 7}{2 ( - 8 )}

b = \frac{- 7 + 7}{2 ( - 8 )} : 0

b = \frac{- 7 - 7}{2 ( - 8 )} : \frac{7}{8}

The solutions to the quadratic equation are:

b = 0, b = \frac{7}{8}

8 x^{2} - 3 x - 2 = 0

x^{2} - 2 x - 62 = 0

0 = - 16 t^{2} + 28 t + 17

(2 x - 3)^{2} = x (3 x - 1)

π r^{2} h = 200

What are the solutions to the equation 7b-3b^2=5b^2 ?
The solutions to the equation 7b-3b^2=5b^2 are b=0,b= 7/8
Find the zeros of 7b-3b^2=5b^2
The zeros of 7b-3b^2=5b^2 are b=0,b= 7/8