What are the solutions to the equation x^2+10x-40=0 ?

The solutions to the equation x^2+10x-40=0 are x=-5+sqrt(65),x=-5-sqrt(65)

Find the zeros of x^2+10x-40=0

The zeros of x^2+10x-40=0 are x=-5+sqrt(65),x=-5-sqrt(65)

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x^{2} + 10 x - 40 = 0

x = - 5 + 65, x = - 5 - 65

Decimal Notation

x = 3.06225 \dots, x = - 13.06225 \dots

Solution steps

x^{2} + 10 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 40) = 265

x_{1, 2} = \frac{- 10 \pm 2 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 65}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 65}{2 \cdot 1}

x = \frac{- 10 + 2 65}{2 \cdot 1} : - 5 + 65

x = \frac{- 10 - 2 65}{2 \cdot 1} : - 5 - 65

The solutions to the quadratic equation are:

x = - 5 + 65, x = - 5 - 65

30 y^{2} - 25000 y + 4375000 = 0

x^{2} - 2 x - 24 = 0

(3 x + 1) (2 x - 1) - (x + 2)^{2} = 5

4 a^{2} + 7 = - 79

u^{2} + 4 u - 12 = 0

What are the solutions to the equation x^2+10x-40=0 ?
The solutions to the equation x^2+10x-40=0 are x=-5+sqrt(65),x=-5-sqrt(65)
Find the zeros of x^2+10x-40=0
The zeros of x^2+10x-40=0 are x=-5+sqrt(65),x=-5-sqrt(65)