What are the solutions to the equation 3x^2-4=x ?

The solutions to the equation 3x^2-4=x are x= 4/3 ,x=-1

Find the zeros of 3x^2-4=x

The zeros of 3x^2-4=x are x= 4/3 ,x=-1

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3 x^{2} - 4 = x

x = \frac{4}{3}, x = - 1

Decimal Notation

x = 1.33333 \dots, x = - 1

Solution steps

3 x^{2} - 4 = x

Move

x

to the left side

3 x^{2} - 4 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

x = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 1

1 - m^{2}

312

\frac{7.2 \cdot 1 0 ^{5}}{0.3 \cdot 1 0 ^{- 8}}

(6 - 2 i) (2 - 3 i)

2 x^{2} - 5 x + 2 = 0

What are the solutions to the equation 3x^2-4=x ?
The solutions to the equation 3x^2-4=x are x= 4/3 ,x=-1
Find the zeros of 3x^2-4=x
The zeros of 3x^2-4=x are x= 4/3 ,x=-1