What are the solutions to the equation completesquare-x^2+4x=0 ?

The solutions to the equation completesquare-x^2+4x=0 are x=4,x=0

Find the zeros of completesquare-x^2+4x=0

The zeros of completesquare-x^2+4x=0 are x=4,x=0

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- x^{2} + 4 x = 0

x = 4, x = 0

Solution steps

- x^{2} + 4 x = 0

Divide both sides by

- 1

\frac{- x ^{2} + 4 x}{- 1} = \frac{0}{- 1}

x^{2} - 4 x = 0

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 4

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

4 x^{2} + 12 x + 3 = 0

2 (2 x - 3)^{2} - 2 (2 x - 3) - 2 = 0

2 x^{(2)} + 3 x = 0

x^{2} + 282 8^{2} = 535 3^{2}

2 x^{2} - (4 x^{2} - 4 x - 4) = 1160

What are the solutions to the equation completesquare-x^2+4x=0 ?
The solutions to the equation completesquare-x^2+4x=0 are x=4,x=0
Find the zeros of completesquare-x^2+4x=0
The zeros of completesquare-x^2+4x=0 are x=4,x=0