What are the solutions to the equation (x+2)^2+x^2=58^2 ?

The solutions to the equation (x+2)^2+x^2=58^2 are x=40,x=-42

Find the zeros of (x+2)^2+x^2=58^2

The zeros of (x+2)^2+x^2=58^2 are x=40,x=-42

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(x + 2)^{2} + x^{2} = 5 8^{2}

x = 40, x = - 42

Solution steps

(x + 2)^{2} + x^{2} = 5 8^{2}

Expand

(x + 2)^{2} + x^{2} : 2 x^{2} + 4 x + 4

Expand

5 8^{2} : 3364

2 x^{2} + 4 x + 4 = 3364

Move

3364

to the left side

2 x^{2} + 4 x - 3360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 3360 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 3360) = 164

x_{1, 2} = \frac{- 4 \pm 164}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 164}{2 \cdot 2}, x_{2} = \frac{- 4 - 164}{2 \cdot 2}

x = \frac{- 4 + 164}{2 \cdot 2} : 40

x = \frac{- 4 - 164}{2 \cdot 2} : - 42

The solutions to the quadratic equation are:

x = 40, x = - 42

- 10 (- 3 x^{2} - 1) = 0

x^{2} - 3 (a + 2) x + b = 2 x - 3 a

x^{2} + 27 x + 50 = 0

4 x^{2} + 8 = 28

4 x^{2} + 8 = 19

What are the solutions to the equation (x+2)^2+x^2=58^2 ?
The solutions to the equation (x+2)^2+x^2=58^2 are x=40,x=-42
Find the zeros of (x+2)^2+x^2=58^2
The zeros of (x+2)^2+x^2=58^2 are x=40,x=-42