What are the solutions to the equation 50=50+2t-0.0625t^2 ?

The solutions to the equation 50=50+2t-0.0625t^2 are t=0,t= 4/(0.125)

Find the zeros of 50=50+2t-0.0625t^2

The zeros of 50=50+2t-0.0625t^2 are t=0,t= 4/(0.125)

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50 = 50 + 2 t - 0.0625 t^{2}

t = 0, t = \frac{4}{0.125}

Decimal Notation

t = 0, t = 32

Solution steps

50 = 50 + 2 t - 0.0625 t^{2}

Switch sides

50 + 2 t - 0.0625 t^{2} = 50

Move

50

to the left side

- 0.0625 t^{2} + 2 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 0.0625 ) \cdot 0}{2 ( - 0.0625 )}

2^{2} - 4 (- 0.0625) \cdot 0 = 2

t_{1, 2} = \frac{- 2 \pm 2}{2 ( - 0.0625 )}

Separate the solutions

t_{1} = \frac{- 2 + 2}{2 ( - 0.0625 )}, t_{2} = \frac{- 2 - 2}{2 ( - 0.0625 )}

t = \frac{- 2 + 2}{2 ( - 0.0625 )} : 0

t = \frac{- 2 - 2}{2 ( - 0.0625 )} : \frac{4}{0.125}

The solutions to the quadratic equation are:

t = 0, t = \frac{4}{0.125}

(2 x - 1)^{2} - 1 = 19

x, x^{2} - y^{2} = x y

a^{2} + a^{2} = x^{2}

4 x^{2} - 5 x^{2} = - 12

- x^{2} + 300 x = 0

What are the solutions to the equation 50=50+2t-0.0625t^2 ?
The solutions to the equation 50=50+2t-0.0625t^2 are t=0,t= 4/(0.125)
Find the zeros of 50=50+2t-0.0625t^2
The zeros of 50=50+2t-0.0625t^2 are t=0,t= 4/(0.125)