What are the solutions to the equation -u^2-3u+4=0 ?

The solutions to the equation -u^2-3u+4=0 are u=-4,u=1

Find the zeros of -u^2-3u+4=0

The zeros of -u^2-3u+4=0 are u=-4,u=1

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- u^{2} - 3 u + 4 = 0

u = - 4, u = 1

Solution steps

- u^{2} - 3 u + 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 4 = 5

u_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 ( - 1 )}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 5}{2 ( - 1 )}, u_{2} = \frac{- ( - 3 ) - 5}{2 ( - 1 )}

u = \frac{- ( - 3 ) + 5}{2 ( - 1 )} : - 4

u = \frac{- ( - 3 ) - 5}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

u = - 4, u = 1

20 a^{2} + 132 a + 160 = 0

(x - 1)^{2} = - 2

x^{2} + 2 x + 9

2 x^{2} + 15 = 23

v^{2} + 11 v = - 28

What are the solutions to the equation -u^2-3u+4=0 ?
The solutions to the equation -u^2-3u+4=0 are u=-4,u=1
Find the zeros of -u^2-3u+4=0
The zeros of -u^2-3u+4=0 are u=-4,u=1