What are the solutions to the equation x^2-x-10=x+5 ?

The solutions to the equation x^2-x-10=x+5 are x=5,x=-3

Find the zeros of x^2-x-10=x+5

The zeros of x^2-x-10=x+5 are x=5,x=-3

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x^{2} - x - 10 = x + 5

x = 5, x = - 3

Solution steps

x^{2} - x - 10 = x + 5

Move

5

to the left side

x^{2} - x - 15 = x

Move

x

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

x^{2} - 6 x - 6 = 0

3 x - 5 = x^{2} - 2 x + 1

4 w^{2} = - w + 3

x^{2} + (k - 1) x + 9 = 0

0.1 x^{2} + 100 x + 8 = 60000

What are the solutions to the equation x^2-x-10=x+5 ?
The solutions to the equation x^2-x-10=x+5 are x=5,x=-3
Find the zeros of x^2-x-10=x+5
The zeros of x^2-x-10=x+5 are x=5,x=-3