What are the solutions to the equation (2x)^2=2x ?

The solutions to the equation (2x)^2=2x are x= 1/2 ,x=0

Find the zeros of (2x)^2=2x

The zeros of (2x)^2=2x are x= 1/2 ,x=0

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(2 x)^{2} = 2 x

x = \frac{1}{2}, x = 0

Decimal

x = 0.5, x = 0

Solution steps

(2 x)^{2} = 2 x

Expand

(2 x)^{2} : 4 x^{2}

4 x^{2} = 2 x

Move

2 x

to the left side

4 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2}{2 \cdot 4} : \frac{1}{2}

x = \frac{- ( - 2 ) - 2}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

4 y^{2} = 20 y

6 s^{2} + 185 = 0

9 x^{2} + 2 x + 1 = 0

3 x^{2} = 14 x + 24

x^{2} - 10 x = - 57

What are the solutions to the equation (2x)^2=2x ?
The solutions to the equation (2x)^2=2x are x= 1/2 ,x=0
Find the zeros of (2x)^2=2x
The zeros of (2x)^2=2x are x= 1/2 ,x=0