What are the solutions to the equation factor 5y^2=7y+6 ?

The solutions to the equation factor 5y^2=7y+6 are y=-3/5 ,y=2

Find the zeros of factor 5y^2=7y+6

The zeros of factor 5y^2=7y+6 are y=-3/5 ,y=2

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5 y^{2} = 7 y + 6

y = - \frac{3}{5}, y = 2

Decimal Notation

y = - 0.6, y = 2

Solution steps

5 y^{2} = 7 y + 6

Move

6

to the left side

5 y^{2} - 6 = 7 y

Move

7 y

to the left side

5 y^{2} - 6 - 7 y = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} - 7 y - 6 = 0

Factor

5 y^{2} - 7 y - 6 : (5 y + 3) (y - 2)

(5 y + 3) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 y + 3 = 0 or y - 2 = 0

Solve

5 y + 3 = 0 : y = - \frac{3}{5}

Solve

y - 2 = 0 : y = 2

The solutions to the quadratic equation are:

y = - \frac{3}{5}, y = 2

2 s^{2} + 15 s + 40 = 0

x, x^{2} + 10 x + 24 = 0

a^{2} - a - 2 = 0

x^{2} + 18 x = 9

x^{2} + 18 x = 4

What are the solutions to the equation factor 5y^2=7y+6 ?
The solutions to the equation factor 5y^2=7y+6 are y=-3/5 ,y=2
Find the zeros of factor 5y^2=7y+6
The zeros of factor 5y^2=7y+6 are y=-3/5 ,y=2