What are the solutions to the equation v^2-7v=18 ?

The solutions to the equation v^2-7v=18 are v=9,v=-2

Find the zeros of v^2-7v=18

The zeros of v^2-7v=18 are v=9,v=-2

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v^{2} - 7 v = 18

v = 9, v = - 2

Solution steps

v^{2} - 7 v = 18

Move

18

to the left side

v^{2} - 7 v - 18 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

v_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, v_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

v = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

v = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

v = 9, v = - 2

x^{2} = 5 x + 24

12 x^{2} - 10 x = 8 x^{2} + 2 x

x, f (3 x - 5) = 2 x^{2} - 3 x + 1

(x + 9)^{2} = 15

272 = - 16 t^{2} + 32 t

What are the solutions to the equation v^2-7v=18 ?
The solutions to the equation v^2-7v=18 are v=9,v=-2
Find the zeros of v^2-7v=18
The zeros of v^2-7v=18 are v=9,v=-2