What are the solutions to the equation 8t^2+24t=2t-5 ?

The solutions to the equation 8t^2+24t=2t-5 are t=-1/4 ,t=-5/2

Find the zeros of 8t^2+24t=2t-5

The zeros of 8t^2+24t=2t-5 are t=-1/4 ,t=-5/2

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8 t^{2} + 24 t = 2 t - 5

t = - \frac{1}{4}, t = - \frac{5}{2}

Decimal Notation

t = - 0.25, t = - 2.5

Solution steps

8 t^{2} + 24 t = 2 t - 5

Move

5

to the left side

8 t^{2} + 24 t + 5 = 2 t

Move

2 t

to the left side

8 t^{2} + 22 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

2 2^{2} - 4 \cdot 8 \cdot 5 = 18

t_{1, 2} = \frac{- 22 \pm 18}{2 \cdot 8}

Separate the solutions

t_{1} = \frac{- 22 + 18}{2 \cdot 8}, t_{2} = \frac{- 22 - 18}{2 \cdot 8}

t = \frac{- 22 + 18}{2 \cdot 8} : - \frac{1}{4}

t = \frac{- 22 - 18}{2 \cdot 8} : - \frac{5}{2}

The solutions to the quadratic equation are:

t = - \frac{1}{4}, t = - \frac{5}{2}

3 y^{2} - 5 y = 0

5 x^{2} - 7 = - 4

x, (x - 1) (x + k) = - 4

x^{2} - \frac{1}{4} x = 0

- 2 x^{2} + 30 = - 7 x

What are the solutions to the equation 8t^2+24t=2t-5 ?
The solutions to the equation 8t^2+24t=2t-5 are t=-1/4 ,t=-5/2
Find the zeros of 8t^2+24t=2t-5
The zeros of 8t^2+24t=2t-5 are t=-1/4 ,t=-5/2