What are the solutions to the equation solvefor x,-493+46x-x^2=0 ?

The solutions to the equation solvefor x,-493+46x-x^2=0 are x=17,x=29

Find the zeros of solvefor x,-493+46x-x^2=0

The zeros of solvefor x,-493+46x-x^2=0 are x=17,x=29

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x, - 493 + 46 x - x^{2} = 0

x = 17, x = 29

Solution steps

- 493 + 46 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 46 x - 493 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 46 \pm 4 6 ^{2} - 4 ( - 1 ) ( - 493 )}{2 ( - 1 )}

4 6^{2} - 4 (- 1) (- 493) = 12

x_{1, 2} = \frac{- 46 \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 46 + 12}{2 ( - 1 )}, x_{2} = \frac{- 46 - 12}{2 ( - 1 )}

x = \frac{- 46 + 12}{2 ( - 1 )} : 17

x = \frac{- 46 - 12}{2 ( - 1 )} : 29

The solutions to the quadratic equation are:

x = 17, x = 29

x^{2} - 9.9 x - 312.5 = 0

E, S = \frac{E ^{2}}{Z}

8 + 4 x - x^{2}

(x - 1)^{2} - 80 = 0

(x + a) = (x + a)^{2}

What are the solutions to the equation solvefor x,-493+46x-x^2=0 ?
The solutions to the equation solvefor x,-493+46x-x^2=0 are x=17,x=29
Find the zeros of solvefor x,-493+46x-x^2=0
The zeros of solvefor x,-493+46x-x^2=0 are x=17,x=29