What are the solutions to the equation 3u^2+11u=-6 ?

The solutions to the equation 3u^2+11u=-6 are u=-2/3 ,u=-3

Find the zeros of 3u^2+11u=-6

The zeros of 3u^2+11u=-6 are u=-2/3 ,u=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 u^{2} + 11 u = - 6

u = - \frac{2}{3}, u = - 3

Decimal Notation

u = - 0.66666 \dots, u = - 3

Solution steps

3 u^{2} + 11 u = - 6

Move

6

to the left side

3 u^{2} + 11 u + 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 6 = 7

u_{1, 2} = \frac{- 11 \pm 7}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- 11 + 7}{2 \cdot 3}, u_{2} = \frac{- 11 - 7}{2 \cdot 3}

u = \frac{- 11 + 7}{2 \cdot 3} : - \frac{2}{3}

u = \frac{- 11 - 7}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

u = - \frac{2}{3}, u = - 3

2 x^{2} = - 5 x - 2

x^{2} + 14 x + 44 = 0

x^{2} - 4 x = 33

2 x^{2} + 3 = - 29

(x - 4) (x - 8) = - 4

What are the solutions to the equation 3u^2+11u=-6 ?
The solutions to the equation 3u^2+11u=-6 are u=-2/3 ,u=-3
Find the zeros of 3u^2+11u=-6
The zeros of 3u^2+11u=-6 are u=-2/3 ,u=-3