What are the solutions to the equation 2x^2+9x+j=0 ?

The solutions to the equation 2x^2+9x+j=0 are x=(-9+sqrt(81-8j))/4 ,x=(-9-sqrt(81-8j))/4

Find the zeros of 2x^2+9x+j=0

The zeros of 2x^2+9x+j=0 are x=(-9+sqrt(81-8j))/4 ,x=(-9-sqrt(81-8j))/4

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2 x^{2} + 9 x + j = 0

x = \frac{- 9 + 81 - 8 j}{4}, x = \frac{- 9 - 81 - 8 j}{4}

Solution steps

2 x^{2} + 9 x + j = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 j}{2 \cdot 2}

Simplify

9^{2} - 4 \cdot 2 j : 81 - 8 j

x_{1, 2} = \frac{- 9 \pm 81 - 8 j}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 81 - 8 j}{2 \cdot 2}, x_{2} = \frac{- 9 - 81 - 8 j}{2 \cdot 2}

x = \frac{- 9 + 81 - 8 j}{2 \cdot 2} : \frac{- 9 + 81 - 8 j}{4}

x = \frac{- 9 - 81 - 8 j}{2 \cdot 2} : \frac{- 9 - 81 - 8 j}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 81 - 8 j}{4}, x = \frac{- 9 - 81 - 8 j}{4}

h^{2} + 3 h - 1 = 0

n (n - 3) = 4 n

9 x^{2} - 18 x + 4 = 0

4 z^{2} + 8 z + 4 = 0

(x) = 0.01 x^{2} + 0.9 x + 2

What are the solutions to the equation 2x^2+9x+j=0 ?
The solutions to the equation 2x^2+9x+j=0 are x=(-9+sqrt(81-8j))/4 ,x=(-9-sqrt(81-8j))/4
Find the zeros of 2x^2+9x+j=0
The zeros of 2x^2+9x+j=0 are x=(-9+sqrt(81-8j))/4 ,x=(-9-sqrt(81-8j))/4