What are the solutions to the equation 3t^2-12t-36=0 ?

The solutions to the equation 3t^2-12t-36=0 are t=6,t=-2

Find the zeros of 3t^2-12t-36=0

The zeros of 3t^2-12t-36=0 are t=6,t=-2

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3 t^{2} - 12 t - 36 = 0

t = 6, t = - 2

Solution steps

3 t^{2} - 12 t - 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 36) = 24

t_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 3}, t_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 3}

t = \frac{- ( - 12 ) + 24}{2 \cdot 3} : 6

t = \frac{- ( - 12 ) - 24}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

t = 6, t = - 2

(x) = 50000 + 200 x + 0.3 x^{2}

x (x - 1) = x + 3

9 x^{2} - 18 x + 3

2 x - x^{2} = 2 - x

3 x^{2} - 15 x + 11 = 0

What are the solutions to the equation 3t^2-12t-36=0 ?
The solutions to the equation 3t^2-12t-36=0 are t=6,t=-2
Find the zeros of 3t^2-12t-36=0
The zeros of 3t^2-12t-36=0 are t=6,t=-2