What are the solutions to the equation 5x^2+3x=36 ?

The solutions to the equation 5x^2+3x=36 are x= 12/5 ,x=-3

Find the zeros of 5x^2+3x=36

The zeros of 5x^2+3x=36 are x= 12/5 ,x=-3

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5 x^{2} + 3 x = 36

x = \frac{12}{5}, x = - 3

Decimal Notation

x = 2.4, x = - 3

Solution steps

5 x^{2} + 3 x = 36

Move

36

to the left side

5 x^{2} + 3 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 36 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 36) = 27

x_{1, 2} = \frac{- 3 \pm 27}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 27}{2 \cdot 5}, x_{2} = \frac{- 3 - 27}{2 \cdot 5}

x = \frac{- 3 + 27}{2 \cdot 5} : \frac{12}{5}

x = \frac{- 3 - 27}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{12}{5}, x = - 3

x = 2 x^{2} - 12 x + 25

0.02 x^{2} + 2 x - 40 = 0

m^{2} - 8 m = 20

n^{2} + n - 930 = 0

(x - 3)^{2} = x (5 - x)

What are the solutions to the equation 5x^2+3x=36 ?
The solutions to the equation 5x^2+3x=36 are x= 12/5 ,x=-3
Find the zeros of 5x^2+3x=36
The zeros of 5x^2+3x=36 are x= 12/5 ,x=-3