What is ((8s^3t^3)^{2/3})/((s^4t^{-8))^{1/4}} ?

The solution to ((8s^3t^3)^{2/3})/((s^4t^{-8))^{1/4}} is 4st^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((8s^3t^3)^{2/3})/((s^4t^{-8))^{1/4}}

simplify

\frac{( 8 s ^{3} t ^{3} ) ^{\frac{2}{3}}}{( s ^{4} t ^{- 8} ) ^{\frac{1}{4}}}

4 s t^{4}

Solution steps

\frac{( 8 s ^{3} t ^{3} ) ^{\frac{2}{3}}}{( s ^{4} t ^{- 8} ) ^{\frac{1}{4}}}

Simplify

(8 s^{3} t^{3})^{\frac{2}{3}} : 4 s^{2} t^{2}

= \frac{4 s ^{2} t ^{2}}{( s ^{4} t ^{- 8} ) ^{\frac{1}{4}}}

Simplify

(s^{4} t^{- 8})^{\frac{1}{4}} : s \frac{1}{t ^{2}}

= \frac{4 s ^{2} t ^{2}}{s \frac{1}{t ^{2}}}

Simplify

\frac{s ^{2}}{s} : s

= \frac{4 s t ^{2}}{\frac{1}{t ^{2}}}

Simplify

\frac{4 s t ^{2}}{\frac{1}{t ^{2}}} : 4 s t^{4}

= 4 s t^{4}

2 x + 7 = 11

\frac{x + 3}{x - 1} \leq \frac{x - 3}{x + 5}

\frac{20 x ^{7} y ^{10}}{y ^{2}}

x^{3} + 6 x^{2} + 5 x - 12

5 \cdot 5

What is ((8s^3t^3)^{2/3})/((s^4t^{-8))^{1/4}} ?
The solution to ((8s^3t^3)^{2/3})/((s^4t^{-8))^{1/4}} is 4st^4