What are the solutions to the equation 2y^2-y+6=0 ?

The solutions to the equation 2y^2-y+6=0 are y= 1/4+i(sqrt(47))/4 ,y= 1/4-i(sqrt(47))/4

Find the zeros of 2y^2-y+6=0

The zeros of 2y^2-y+6=0 are y= 1/4+i(sqrt(47))/4 ,y= 1/4-i(sqrt(47))/4

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2 y^{2} - y + 6 = 0

y = \frac{1}{4} + i \frac{47}{4}, y = \frac{1}{4} - i \frac{47}{4}

Solution steps

2 y^{2} - y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 6 : 47 i

y_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 2}, y_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 2}

y = \frac{- ( - 1 ) + 47 i}{2 \cdot 2} : \frac{1}{4} + i \frac{47}{4}

y = \frac{- ( - 1 ) - 47 i}{2 \cdot 2} : \frac{1}{4} - i \frac{47}{4}

The solutions to the quadratic equation are:

y = \frac{1}{4} + i \frac{47}{4}, y = \frac{1}{4} - i \frac{47}{4}

a^{2} - 12 a = - 27

4 x^{2} + 232 = - 64 x

- 16 x^{2} + 12 x + 40 = 0

4 x^{2} + 1 - 5 = 0

2 (x - 6)^{2} - 2 = 30

What are the solutions to the equation 2y^2-y+6=0 ?
The solutions to the equation 2y^2-y+6=0 are y= 1/4+i(sqrt(47))/4 ,y= 1/4-i(sqrt(47))/4
Find the zeros of 2y^2-y+6=0
The zeros of 2y^2-y+6=0 are y= 1/4+i(sqrt(47))/4 ,y= 1/4-i(sqrt(47))/4