What are the solutions to the equation (1-x)(4-x)-4=0 ?

The solutions to the equation (1-x)(4-x)-4=0 are x=5,x=0

Find the zeros of (1-x)(4-x)-4=0

The zeros of (1-x)(4-x)-4=0 are x=5,x=0

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(1 - x) (4 - x) - 4 = 0

x = 5, x = 0

Solution steps

(1 - x) (4 - x) - 4 = 0

Expand

(1 - x) (4 - x) - 4 : x^{2} - 5 x

x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

x^{2} = 3 x - \frac{1}{8}

\frac{1}{3} x^{2} - x - 18 = 0

x (x + 7) = - 12

x^{2} + 17 x + 77 = 0

14 x^{2} - 11 x = 3

What are the solutions to the equation (1-x)(4-x)-4=0 ?
The solutions to the equation (1-x)(4-x)-4=0 are x=5,x=0
Find the zeros of (1-x)(4-x)-4=0
The zeros of (1-x)(4-x)-4=0 are x=5,x=0