What are the solutions to the equation (2+2x)(4+2x)=72 ?

The solutions to the equation (2+2x)(4+2x)=72 are x=(-3+sqrt(73))/2 ,x=-(3+sqrt(73))/2

Find the zeros of (2+2x)(4+2x)=72

The zeros of (2+2x)(4+2x)=72 are x=(-3+sqrt(73))/2 ,x=-(3+sqrt(73))/2

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(2 + 2 x) (4 + 2 x) = 72

x = \frac{- 3 + 73}{2}, x = - \frac{3 + 73}{2}

Decimal Notation

x = 2.77200 \dots, x = - 5.77200 \dots

Solution steps

(2 + 2 x) (4 + 2 x) = 72

Expand

(2 + 2 x) (4 + 2 x) : 8 + 12 x + 4 x^{2}

8 + 12 x + 4 x^{2} = 72

Move

72

to the left side

4 x^{2} + 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 64 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 64) = 473

x_{1, 2} = \frac{- 12 \pm 4 73}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 73}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 73}{2 \cdot 4}

x = \frac{- 12 + 4 73}{2 \cdot 4} : \frac{- 3 + 73}{2}

x = \frac{- 12 - 4 73}{2 \cdot 4} : - \frac{3 + 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 73}{2}, x = - \frac{3 + 73}{2}

(x + 7)^{2} - 6 (x + 7) = 0

a^{2} - 15 = 21

3 x^{2} - 9 = - 36

7.2 = 1225 x^{2}

2 x^{2} - 11 x = - 5

What are the solutions to the equation (2+2x)(4+2x)=72 ?
The solutions to the equation (2+2x)(4+2x)=72 are x=(-3+sqrt(73))/2 ,x=-(3+sqrt(73))/2
Find the zeros of (2+2x)(4+2x)=72
The zeros of (2+2x)(4+2x)=72 are x=(-3+sqrt(73))/2 ,x=-(3+sqrt(73))/2