What is ((2/3)^2\times (5+4))/((7-5)^2) ?

The solution to ((2/3)^2\times (5+4))/((7-5)^2) is 1

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simplify ((2/3)^2\times (5+4))/((7-5)^2)

simplify

\frac{( \frac{2}{3} ) ^{2} \cdot ( 5 + 4 )}{( 7 - 5 ) ^{2}}

1

Solution steps

\frac{( \frac{2}{3} ) ^{2} ( 5 + 4 )}{( 7 - 5 ) ^{2}}

Simplify

(\frac{2}{3})^{2} (5 + 4) : 4

= \frac{4}{( 7 - 5 ) ^{2}}

Subtract the numbers:

7 - 5 = 2

= \frac{4}{2 ^{2}}

Factor the number:

4 = 2^{2}

= \frac{2 ^{2}}{2 ^{2}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

\frac{10}{3 - 4 i}

6 3^{2}

(x^{2} + y^{2})^{\frac{3}{2}}

5 a^{5} b^{2} - 8 a^{4} b^{3} + 3 a^{3} b^{4}

4 y^{2} + 12 y + 5 = 0

What is ((2/3)^2\times (5+4))/((7-5)^2) ?
The solution to ((2/3)^2\times (5+4))/((7-5)^2) is 1