What are the solutions to the equation 0=2x^2-x+3 ?

The solutions to the equation 0=2x^2-x+3 are x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4

Find the zeros of 0=2x^2-x+3

The zeros of 0=2x^2-x+3 are x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4

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0 = 2 x^{2} - x + 3

x = \frac{1}{4} + i \frac{23}{4}, x = \frac{1}{4} - i \frac{23}{4}

Solution steps

0 = 2 x^{2} - x + 3

Switch sides

2 x^{2} - x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 3 : 23 i

x_{1, 2} = \frac{- ( - 1 ) \pm 23 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 23 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 23 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 23 i}{2 \cdot 2} : \frac{1}{4} + i \frac{23}{4}

x = \frac{- ( - 1 ) - 23 i}{2 \cdot 2} : \frac{1}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{23}{4}, x = \frac{1}{4} - i \frac{23}{4}

(x - 2) \cdot (x - 5) = 0

x, 3 x^{2} - 7 x = - 2

x, z = y^{2} - 1 x^{2}

x^{2} + 84 x + 1681 = 0

64 - 0.25 x^{2} = 0

What are the solutions to the equation 0=2x^2-x+3 ?
The solutions to the equation 0=2x^2-x+3 are x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4
Find the zeros of 0=2x^2-x+3
The zeros of 0=2x^2-x+3 are x= 1/4+i(sqrt(23))/4 ,x= 1/4-i(sqrt(23))/4