What are the solutions to the equation -16a^2+164a+36=0 ?

The solutions to the equation -16a^2+164a+36=0 are a=-(-41+5sqrt(73))/8 ,a=(41+5sqrt(73))/8

Find the zeros of -16a^2+164a+36=0

The zeros of -16a^2+164a+36=0 are a=-(-41+5sqrt(73))/8 ,a=(41+5sqrt(73))/8

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- 16 a^{2} + 164 a + 36 = 0

a = - \frac{- 41 + 5 73}{8}, a = \frac{41 + 5 73}{8}

Decimal Notation

a = - 0.21500 \dots, a = 10.46500 \dots

Solution steps

- 16 a^{2} + 164 a + 36 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 164 \pm 16 4 ^{2} - 4 ( - 16 ) \cdot 36}{2 ( - 16 )}

16 4^{2} - 4 (- 16) \cdot 36 = 2073

a_{1, 2} = \frac{- 164 \pm 20 73}{2 ( - 16 )}

Separate the solutions

a_{1} = \frac{- 164 + 20 73}{2 ( - 16 )}, a_{2} = \frac{- 164 - 20 73}{2 ( - 16 )}

a = \frac{- 164 + 20 73}{2 ( - 16 )} : - \frac{- 41 + 5 73}{8}

a = \frac{- 164 - 20 73}{2 ( - 16 )} : \frac{41 + 5 73}{8}

The solutions to the quadratic equation are:

a = - \frac{- 41 + 5 73}{8}, a = \frac{41 + 5 73}{8}

- 4 x^{2} - 12 x + 3 = 0

l, l^{2} + m^{2} + n^{2} = 1

- 6 x^{2} = 3 x + 6

3 p^{2} - 5 p - 12 = 0

a^{2} + 6 a + 5 = 0

What are the solutions to the equation -16a^2+164a+36=0 ?
The solutions to the equation -16a^2+164a+36=0 are a=-(-41+5sqrt(73))/8 ,a=(41+5sqrt(73))/8
Find the zeros of -16a^2+164a+36=0
The zeros of -16a^2+164a+36=0 are a=-(-41+5sqrt(73))/8 ,a=(41+5sqrt(73))/8