What are the solutions to the equation completesquare 7j^2-3j=-j+9 ?

The solutions to the equation completesquare 7j^2-3j=-j+9 are j= 9/7 ,j=-1

Find the zeros of completesquare 7j^2-3j=-j+9

The zeros of completesquare 7j^2-3j=-j+9 are j= 9/7 ,j=-1

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7 j^{2} - 3 j = - j + 9

j = \frac{9}{7}, j = - 1

Decimal Notation

j = 1.28571 \dots, j = - 1

Solution steps

7 j^{2} - 3 j = - j + 9

Move

j

to the left side

7 j^{2} - 2 j = 9

Divide both sides by

7

\frac{7 j ^{2} - 2 j}{7} = \frac{9}{7}

j^{2} - \frac{2 j}{7} = \frac{9}{7}

Rewrite in the form

(x + a)^{2} = b

(j - \frac{1}{7})^{2} = \frac{64}{49}

For

the solutions are

f (x) = a, - a

Solve

j - \frac{1}{7} = \frac{64}{49} : j = \frac{9}{7}

Solve

j - \frac{1}{7} = - \frac{64}{49} : j = - 1

The solutions to the quadratic equation are:

j = \frac{9}{7}, j = - 1

8 x^{2} = 5 x + 3

- 4 x^{2} - 12 x + 1 = 0

2 x^{2} - 8 = - 80

x^{2} - 14 x - 28 = 0

x^{2} = \frac{100}{169}

What are the solutions to the equation completesquare 7j^2-3j=-j+9 ?
The solutions to the equation completesquare 7j^2-3j=-j+9 are j= 9/7 ,j=-1
Find the zeros of completesquare 7j^2-3j=-j+9
The zeros of completesquare 7j^2-3j=-j+9 are j= 9/7 ,j=-1