What is simplify-(5a^2bc)^2*(5abc)^{-3} ?

The solution to simplify-(5a^2bc)^2*(5abc)^{-3} is -a/(5bc)

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simplify-(5a^2bc)^2*(5abc)^{-3}

simplify

- (5 a^{2} b c)^{2} \cdot (5 ab c)^{- 3}

- \frac{a}{5 b c}

Solution steps

- (5 a^{2} b c)^{2} (5 ab c)^{- 3}

Simplify

(5 a^{2} b c)^{2} : 25 a^{4} b^{2} c^{2}

= - 25 a^{4} b^{2} c^{2} (5 ab c)^{- 3}

Simplify

(5 ab c)^{- 3} : \frac{1}{125 a ^{3} b ^{3} c ^{3}}

= - 25 a^{4} b^{2} c^{2} \frac{1}{125 a ^{3} b ^{3} c ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{25 a ^{4} b ^{2} c ^{2} \cdot 1}{125 a ^{3} b ^{3} c ^{3}}

Multiply the numbers:

25 \cdot 1 = 25

= - \frac{25 a ^{4} b ^{2} c ^{2}}{125 a ^{3} b ^{3} c ^{3}}

Factor the number:

125 = 25 \cdot 5

= - \frac{25 a ^{4} b ^{2} c ^{2}}{25 \cdot 5 a ^{3} b ^{3} c ^{3}}

Cancel the common factor:

25

= - \frac{a ^{4} b ^{2} c ^{2}}{5 a ^{3} b ^{3} c ^{3}}

Simplify

\frac{a ^{4}}{a ^{3}} : a

= - \frac{a b ^{2} c ^{2}}{5 b ^{3} c ^{3}}

Simplify

\frac{b ^{2}}{b ^{3}} : \frac{1}{b}

= - \frac{a c ^{2}}{5 b c ^{3}}

Simplify

\frac{c ^{2}}{c ^{3}} : \frac{1}{c}

= - \frac{a}{5 b c}

∣ x - 2 ∣ = 7

x^{2} + 14 x + 50 = 0

2 \leq 3 - 2 (x + 1) < 8

9^{2} + 1 2^{2}

121 x^{2} + 24 x + 2 = 0

What is simplify-(5a^2bc)^2*(5abc)^{-3} ?
The solution to simplify-(5a^2bc)^2*(5abc)^{-3} is -a/(5bc)