What are the solutions to the equation -x^2-5x+10=0 ?

The solutions to the equation -x^2-5x+10=0 are x=-(5+sqrt(65))/2 ,x=(sqrt(65)-5)/2

Find the zeros of -x^2-5x+10=0

The zeros of -x^2-5x+10=0 are x=-(5+sqrt(65))/2 ,x=(sqrt(65)-5)/2

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- x^{2} - 5 x + 10 = 0

x = - \frac{5 + 65}{2}, x = \frac{65 - 5}{2}

Decimal Notation

x = - 6.53112 \dots, x = 1.53112 \dots

Solution steps

- x^{2} - 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 10 = 65

x_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 65}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 65}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 65}{2 ( - 1 )} : - \frac{5 + 65}{2}

x = \frac{- ( - 5 ) - 65}{2 ( - 1 )} : \frac{65 - 5}{2}

The solutions to the quadratic equation are:

x = - \frac{5 + 65}{2}, x = \frac{65 - 5}{2}

x^{2} + 2 x - 18

x^{2} (- 8 b + 7) = - 8 b + 6

x, x (x - 5) = 0

0 = 40 - 10 t - 5 t^{2}

10 n^{2} - 3 n - 1 = 0

What are the solutions to the equation -x^2-5x+10=0 ?
The solutions to the equation -x^2-5x+10=0 are x=-(5+sqrt(65))/2 ,x=(sqrt(65)-5)/2
Find the zeros of -x^2-5x+10=0
The zeros of -x^2-5x+10=0 are x=-(5+sqrt(65))/2 ,x=(sqrt(65)-5)/2