What are the solutions to the equation k^2+6=22 ?

The solutions to the equation k^2+6=22 are k=4,k=-4

Find the zeros of k^2+6=22

The zeros of k^2+6=22 are k=4,k=-4

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k^{2} + 6 = 22

k = 4, k = - 4

Solution steps

k^{2} + 6 = 22

Move

6

to the right side

k^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 16, k = - 16

16 = 4

- 16 = - 4

k = 4, k = - 4

2 x^{2} + 3 x - 629 = 0

\frac{1}{3} x = 10 - x^{2}

(x + 4) (x - 3) = 10

4 (x + 5)^{2} + 20 = 12

2 x (x - 2) = 10 x^{2} - 5 x

What are the solutions to the equation k^2+6=22 ?
The solutions to the equation k^2+6=22 are k=4,k=-4
Find the zeros of k^2+6=22
The zeros of k^2+6=22 are k=4,k=-4