What are the solutions to the equation 0=6x^2-7x-22 ?

The solutions to the equation 0=6x^2-7x-22 are x=(7+sqrt(577))/(12),x=(7-sqrt(577))/(12)

Find the zeros of 0=6x^2-7x-22

The zeros of 0=6x^2-7x-22 are x=(7+sqrt(577))/(12),x=(7-sqrt(577))/(12)

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0 = 6 x^{2} - 7 x - 22

x = \frac{7 + 577}{12}, x = \frac{7 - 577}{12}

Decimal Notation

x = 2.58506 \dots, x = - 1.41840 \dots

Solution steps

0 = 6 x^{2} - 7 x - 22

Switch sides

6 x^{2} - 7 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 22 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 22) = 577

x_{1, 2} = \frac{- ( - 7 ) \pm 577}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 577}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 577}{2 \cdot 6}

x = \frac{- ( - 7 ) + 577}{2 \cdot 6} : \frac{7 + 577}{12}

x = \frac{- ( - 7 ) - 577}{2 \cdot 6} : \frac{7 - 577}{12}

The solutions to the quadratic equation are:

x = \frac{7 + 577}{12}, x = \frac{7 - 577}{12}

2 x^{2} - 40 = 0

2 x^{2} + 1 = 9

5 x^{2} + 1 = 31

10 x^{2} + 32 x + 6 = 0

5 x^{2} + 1 = 11

What are the solutions to the equation 0=6x^2-7x-22 ?
The solutions to the equation 0=6x^2-7x-22 are x=(7+sqrt(577))/(12),x=(7-sqrt(577))/(12)
Find the zeros of 0=6x^2-7x-22
The zeros of 0=6x^2-7x-22 are x=(7+sqrt(577))/(12),x=(7-sqrt(577))/(12)