What are the solutions to the equation 13x^2-12x-2=0 ?

The solutions to the equation 13x^2-12x-2=0 are x=(6+sqrt(62))/(13),x=(6-sqrt(62))/(13)

Find the zeros of 13x^2-12x-2=0

The zeros of 13x^2-12x-2=0 are x=(6+sqrt(62))/(13),x=(6-sqrt(62))/(13)

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13 x^{2} - 12 x - 2 = 0

x = \frac{6 + 62}{13}, x = \frac{6 - 62}{13}

Decimal Notation

x = 1.06723 \dots, x = - 0.14415 \dots

Solution steps

13 x^{2} - 12 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 13 ( - 2 )}{2 \cdot 13}

(- 12)^{2} - 4 \cdot 13 (- 2) = 262

x_{1, 2} = \frac{- ( - 12 ) \pm 2 62}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 62}{2 \cdot 13}, x_{2} = \frac{- ( - 12 ) - 2 62}{2 \cdot 13}

x = \frac{- ( - 12 ) + 2 62}{2 \cdot 13} : \frac{6 + 62}{13}

x = \frac{- ( - 12 ) - 2 62}{2 \cdot 13} : \frac{6 - 62}{13}

The solutions to the quadratic equation are:

x = \frac{6 + 62}{13}, x = \frac{6 - 62}{13}

49 t^{2} = 4

x^{2} - 5 x - 48 = 0

a + g (a) = - x^{2} + 4 x

(y + 1)^{2} = 16

x^{2} + 2 x = 10 x + 20

What are the solutions to the equation 13x^2-12x-2=0 ?
The solutions to the equation 13x^2-12x-2=0 are x=(6+sqrt(62))/(13),x=(6-sqrt(62))/(13)
Find the zeros of 13x^2-12x-2=0
The zeros of 13x^2-12x-2=0 are x=(6+sqrt(62))/(13),x=(6-sqrt(62))/(13)